【11-27 问题求助】懂代码的霸霸萌，可以帮我康康这个跳动

【11-27 问题求助】懂代码的霸霸萌，可以帮我康康这个跳动的玩意怎么能从3个一循环改成6个一循环吗
(这是.ini文件代码)
[Rainmeter]
Update=31
[Metadata]
Author=Real
Name=Real'sToy
Information=
Version=
License=Creative Commons，GNU Public License，MIT License
[Variables]
text1=welcome
text2=2
text3=3
text4=
text5=
text6=
[BG]
Meter=Image
W=130
H=320
SolidColor=00000001
[MeasureScript]
Measure=Script
ScriptFile=move.l ua
[MRound]
Measure=Calc
Formula=0
[Pic]
Meter=Rotator
Measurename=MRound
ImageName=pic2
Startangle=0
OffsetX=41
OffsetY=41
x=50
Y=0
w=80
h=80
DynamicVariables=1
[Text]
Meter=String
Text=#text1#
X=90
Y=310
AntiAlias=1
StringAlign=center
InlineSetting2=Size | 25
InlineSetting3=Face | 方正兰亭超细黑简体
(这是.lua文件)
function Initialize()
SeO = '!SetOption'
picn = 3
picc = 0
textn = 3
textc = 0
k = -1
n = 39
height=220
end
function Update()
Add()
Round()
Jump()
picchange()
color()
textchange()
end
function Add( ... )
k = k + 1
if k == n + 1 then k = 0 end
end
function Jump( ... )
h1 = math.cos(k/n*math.pi)
h2 = math.abs(math.tan(k/n*math.pi))*1.4
h = height-(math.abs(h1)*height)+h2
SKIN:Bang(SeO, 'Pic', 'Y' ,h)
end
function Round( ... )
r = k/n
SKIN:Bang(SeO, 'MRound', 'Formula' ,r)
end
function picchange( ... )
if k == (n+1)/2 then
picc = picc + 1
SKIN:Bang(SeO, 'Pic', 'ImageName' ,'pic'..picc)
if picc == picn then picc = 0 end
end
end
function color( ... )
local c1 = 0
local c2 = 0
if k >= (n+1)/2 then
c1 = k/(n+1)*2*155-155
c2 = 255
end
if k < (n+1)/2 then
c1 = 155-k/(n+1)*2.1*155
c2 = 255-k/(n+1)*2.1*255
end
co = 'GradientColor | 0 | 255,255,255,'..c1..' ; 0.0 | 255,255,255,'..c2..' ; 0.5| 255,255,255,'..c1..' ;1.0'
SKIN:Bang(SeO, 'text', 'InlineSetting' ,co)
end
function textchange( ... )
if k == (n+1)/2 then
textc = textc + 1
SKIN:Bang(SeO, 'Text', 'Text' ,'#text'..textc..'#')
if textc == textn then textc = 0 end
end
end